if you Choose an Answer to this Question, what is the Chance that you will be Correct

We will try to solve the famous mathematical probability paradox in this post, which goes like this:

if you choose an answer to this question at random,

what is the chance you will be correct?

(A) 25% 

(B) 50% 

(C) 60% 

(D) 25%

******** STEP 1 ********

We will have to assume that this is a multiple choice question (MCQ), as there are 2 options - A & D - with the same answer (25%)

So, we have 4 options.

Following are the logic formulas that we will use to solve the problem:

Logic S

If only 1 option of the 4 options is correct, then the probability would be =

1/4 =  25%

Logic K

If 2 options of the 4 options are correct, then the probability would be =

2/4 =  50%

Logic G

If 3 options of the 4 options are correct, then the probability would be =

3/4 =  75%

Logic Z

If only all 4 options are correct, then the probability would be =

4/4 =  100%

Logic V

If none of 4 options are correct, then the probability would be =

0/4 =  0%

******** STEP 2 ********

As we can see in the logic S/K/G/Z, 

a 60% probability of getting the right answer does not exist.

So, we rule out option C

If option A is correct, then option D will also be correct.

Or to say, 2 options are correct.

So, going by logic K:

if 2 options of the 4 options are correct, then the probability would be =

2/4 =  50%

But the value of A & D is 25%

So, we rule out both options A & D

Finally, if option B is correct.

Or to say, 1 options is correct.

So, going by logic S:

if only 1 option of the 4 options is correct, then the probability would be =

1/4 =  25%

But the value of B is 50%

So, we rule out option B

******** STEP 3 ********

Summary/Answer is hence, that there is no correct answer.

Or to say, 0 option is correct.

So, going by logic V:

if none of the 4 options is correct, then the probability would be =

0/4 =  0%

Which is unfortunately not listed here!

And, that's the reason that this questions is a paradox.